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(x^2)-5x-6400=0
a = 1; b = -5; c = -6400;
Δ = b2-4ac
Δ = -52-4·1·(-6400)
Δ = 25625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25625}=\sqrt{625*41}=\sqrt{625}*\sqrt{41}=25\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25\sqrt{41}}{2*1}=\frac{5-25\sqrt{41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25\sqrt{41}}{2*1}=\frac{5+25\sqrt{41}}{2} $
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